The current in an RL circuit builds up to one-third of its steady-state value in 4.91 s. Find the inductive time constant.
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The current in an RL circuit builds up to one-third of its steady-state value in 4.91...
Chapter 30, Problem 050 The current in an RL circuit builds up to one-third of its steady-state value in 6.85 s. Find the inductive time constant. Number Units
8. -/10 points My Notes Ask Your Teacher An electrical engineer designed an RL circuit similar to the one shown in the figure, with € -6.00 V, L - 3.40 m, and R - 5.60 0. R (a) What is the inductive time constant of the circuit (in ms)? cms (b) Calculate the current in the circuit (in A) 250 us after the switch is closed. СА (c) What is the value of the final steady-state current (in A)? ГА...
RL Circuits The current in the RL circuit shown below reaches half its maximum value in 1.75 ms after the switch S1 is thrown. Determine (a) the time constant of the circuit and (b) the resistance of the circuit if L = 250 mH.
The current in an RL circuit drops from 1.70 A to 33.0 mA in the first second following removal of the battery from the circuit. Find the inductive time constant. If A is 24.0 H, find the resistance R in the circuit.
The current in an RL circuit increases to 98 % of its final value 2.22 safter the switch is closed. PART A) What is the time constant for this circuit? PART B) If the inductance in the circuit is 0.298 H , what is the resistance?
The current in the RL circuit shown below reaches two-thirds its maximum value in 2.00 ms after the switch S, is thrown. 0000 as (a) Determine the time constant of the circuit (in ms). ms (b) Determine the resistance of the circuit (in ) if L = 600 mH.
The current in the RL circuit shown below reaches three-fifths its maximum value in 3.75 ms after the switch S, is thrown. 0000 (a) Determine the time constant of the circuit (in ms). 7.34 x ms (b) Determine the resistance of the circuit (in ) if L = 150 mH.
In a RL series circuit, the current reaches half its maximum value in 2.0 s after the switch is closed. If the resistance is 5.0 Ω, find the inductance of the inductor. (4 pts) In a RL series circuit, the current reaches half its maximum value in 2.0 s after the switch is closed. 5) If the resistance is 5.0 Ω, find the inductance of the inductor. (4 pts)
4. The current in an RL circuit increases to 95% of its final value 3 seconds after the switch is closed. The inductance in the circuit is 0.310 H. Find the inductive time constant and resistance for the circuit. (Assume the inductor has neglible resistance). Show your work. 5. At resonance, the reactance of the inductor (L) and the capacitor (C) cancel each other so that the impedance (Z) is just the resistance (R). Using the values from this experiment...
GOAL Calculate a time constant and relate it to current in an RL circuit. PROBLEM A 12.6-V battery is in a circuit with a 30.0-mH inductor and a 0.150-? resistor. The switch is closed at t = 0. (a) Find the time constant of the circuit. (b) Find the current after one time constant has elapsed. (c) Find the voltage drops across the resistor when t = 0 and t = one time constant. (d) What's the rate of change...