Write with radicals. Assume that the variable represents positive real numbers (An) /3 -5/3 ( A....
Simplify Assume that the variable represents a positive real number.
We write R+ for the set of positive real numbers. For any positive real number e, we write (-6, 6) = {x a real number : -e < x <e}. Prove that the intersection of all such intervals is the set containing zero, n (-e, e) = {0} EER+
We write R+ for the set of positive real numbers. For any positive real number e, we write (-6, 6) = {x a real number : -e < x <e}. Prove that the intersection of all such intervals is the set containing zero, n (-e, e) = {0} EER+
Expand the given logarithmic expression. Assume all the variable expressions represent positive real numbers. When possible, evaluate logarithmic expression. Do not use calculator. ln(e^6/xy^5)
5. Subtract the radical expressions. Assume that all variables represent positive real numbers. 372y3 - Jy O A. 172y3 - 2y B. It can't be simplified further. C.3/17y9 - 2y D. (18y - 1) 2y
3- Simplify. Assume all variables represent positive real numbers. a) 11/x7-7x4x +24/ b) 3 72m2 -5/32m2 -3118m2 c7N7+NI4) d) V2(5 72-4 50)
Simplify completely. The answer should contain only positive exponents. Assume all variables represent positive real numbers. Do not use radical form and express any number as an integer or simplified fraction. 32u22 3/5 4,,5
Simplify 3 6 r v Assume that all variables represent positive real numbers.
5 numbers chosen randomly without replacement. "B" represents number of even numbers, this random variable has this probability: x 0 1 2 3 4 5 p(B=x) 0.02693 0.15989 .33858 .31977 .13464 .02020 number of odd #s chosen would then be 5-x, if x is even #s chosen. "C" represents difference b/w # of even and # of odd chosen, --> C= 2B-5 a. probability that exactly 1 even # chosen? b. probability at most 1 even # chosen? c. prob....
Assume the variable LIST is defined as a list of numbers. Write a code segment that utilizes a loop to total up all of the numbers in the list up to, but not including, the first negative number. Store the result in the variable TOTAL. % test cases % LIST = [ 1 4 6 -2 7 9]; TOTAL = 11; % LIST = [ -2 4 5 7 9]; TOTAL = 0; % your code segment here %----------------------- %...