Question

What is the potential in volts at a distance of 140 pm from a Ti⁴⁺ ion? (The answer should be written as a number with two digits to the right of the decimal and with the correct sign.)

Answer 1

Solution

Answer: +41.14 Volts

Assuming the Ti4+ ion to be a point charge of charge ,

Electronic charge is e=1.6*10^{-19} C

Thus potential at a distance of,

R = 140pm = 140 * 10-12m

Is,

$V=\frac{1}{4\pi \epsilon_0}\frac{Q}{R}=(9*10^9)*\frac{6.4*10^{-19}}{140*10^{-12}}=41.143Volts$(Standard value of 1/4pi epsilon is 9*10^9 m/F)

Thus rounding off to two decimal place,

$V=41.14Volts$