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This problem can be solved by two different way...
1) Analytical method...
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2) Graphical method...
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Find the line-to-line source voltage Vbc a4 an nN Given ZL=V3Ω and Z=jV3Ω abc phase sequence...
Find the line-to-line source voltage Vb bc AB Zi an nN Given ZL-V3Ω and Z=JV3Ω abc...
Find the line-to-line source voltage Vb bc AB Zi an nN Given ZL-V3Ω and Z=JV3Ω abc phase sequence with V 120v3430° v 0 208V20% 0 360v2-60% 120V2-1200 300V -70%
Given the circuit in the following figure, ZL 220/-120 V z ZL 220/120 V7 where Z1...
Given the circuit in the following figure, ZL 220/-120 V z ZL 220/120 V7 where Z1 = 2 + j 1.5 Ω and ZL-15 + j8 Ω. a. Determine current LAB and voltage VBc. b. If a capacitor Zc- 10/phase was installed in parallel with the load, repeat the calculation of part 2.a.
A balanced positive-sequence wye-connected 60-Hz three-phase source has line-to-line voltages of VL = 440 V rms....
A balanced positive-sequence wye-connected 60-Hz three-phase source has line-to-line voltages of VL = 440 V rms. This source is connected to a balanced wye-connected load. Each phase of the load consists of a 0.5-H inductance in series with a 50-Ω resistance. Assume that the phase of Van is zero. home / study / engineering / electrical engineering / electrical engineering questions and answers / A Balanced Positive-sequence Wye-connected 60-Hz Three-phase Source Has Line-to-line Voltages ... Question: A balanced positive-sequence wye-connected...
1. In a three-phase balanced wye-wye system, the source is an abc-positive sequence set of voltag...
1. In a three-phase balanced wye-wye system, the source is an abc-positive sequence set of voltages with Van- 120 20 Vrms. The per phase impedance of the load is 5 +j62. If the line impedance per phase is 0 Ω, find the line currents, the line to line voltages at the source, and the line to line voltages at the load 120 20 Vms 2. In a three-phase balanced wye-wye system, the source is an abc-sequence set of voltages with...
I. A balanced three-phase positive sequence wye-connected 60Hz source voltage has line-neutral voltage of V, 1000 V. It is connected to a three- phase wye connected load whose impedance is z 50+j...
I. A balanced three-phase positive sequence wye-connected 60Hz source voltage has line-neutral voltage of V, 1000 V. It is connected to a three- phase wye connected load whose impedance is z 50+j37.7 2 a. Find line currents ia ib, ic and line-line voltages Vab, Vbo Vac b. Find the total complex power delivered to the load. c. Find delta-connected capacitor bank needed to bring the PF to 0.95 (lagging) of system. d. Re-calculate currents la, ib, io with Case c....
I. A balanced three-phase positive sequence wye-connected 60Hz source voltage has line-neutral voltage of V, 1000 V. It is connected to a three- phase wye connected load whose impedance is z 50+j...
I. A balanced three-phase positive sequence wye-connected 60Hz source voltage has line-neutral voltage of V, 1000 V. It is connected to a three- phase wye connected load whose impedance is z 50+j37.7 2 a. Find line currents ia ib, ic and line-line voltages Vab, Vbo Vac b. Find the total complex power delivered to the load. c. Find delta-connected capacitor bank needed to bring the PF to 0.95 (lagging) of system. d. Re-calculate currents la, ib, io with Case c....
please solve as soon as possible, thank you. Q3: For the following circuit, Z;=6+j9.2, Z=2+j112, ZL=2-310...
please solve as soon as possible, thank you.
Q3: For the following circuit, Z;=6+j9.2, Z=2+j112, ZL=2-310 S2, Vab= 90 cos(120xt+10°) V, Vbc= 90 cos(120t-110°) V, Vca= 90 cos(120xt+130°) V. Vbc Z, Fig. Q3: the circuit of Q3. a) Find the line currents I, I, and Ic. (15 marks) b) Compute the current through each voltage source, 11, 12, and 13. (9 marks) c) Find the reactive power produced by each voltage source in the delta configuration. (6 marks)
In a three-phase balanced wye-wye system, the source is an abc-positive sequence set of voltages with...
In a three-phase balanced wye-wye system, the source is an abc-positive sequence set of voltages with Van = 120 000 Vrms. The per phase impedance of the load is 5 +J60. If the line impedance per phase is 0 0, find the line currents, the line to line voltages at the source, and the line to line voltages at the load. 1. Van 120 0" Vrms ZY = 5+j Va VA neutral
(15 points) In a balanced three-phase wye-delta system, the source has a positive (abc) phase sequence...
(15 points) In a balanced three-phase wye-delta system, the source has a positive (abc) phase sequence and a phase voltage of Van 200VrmsZ - 30°. If the line impedance is zero and the line current is LaA -6ArmsZ- 65°, find the load impedance per phase in the delta. AB AB Arms
Note Unless otherwise specified, three phase systems are rated in terms of their line-to-line rms voltages So, for instance, a three-phase 230 kV transmission line has an rms phase voltage of 230/V3...
Note Unless otherwise specified, three phase systems are rated in terms of their line-to-line rms voltages So, for instance, a three-phase 230 kV transmission line has an rms phase voltage of 230/V3 kV. If you encounter a three-phase system specified with two voltages, e.g., 480/277 V, that implies that the line-to-line rms voltage is 480 V and the rms phase voltage is 277 v. Problem 8 The line-to-line voltage of a three-phase transmission line is Vbc-120 2.20° kV. Suppose the...
Find the line-to-line source voltage Vb bc AB Zi an nN Given ZL-V3Ω and Z=JV3Ω abc phase sequence with V 120v3430° v 0 208V20% 0 360v2-60% 120V2-1200 300V -70%
Given the circuit in the following figure, ZL 220/-120 V z ZL 220/120 V7 where Z1 = 2 + j 1.5 Ω and ZL-15 + j8 Ω. a. Determine current LAB and voltage VBc. b. If a capacitor Zc- 10/phase was installed in parallel with the load, repeat the calculation of part 2.a.
1. In a three-phase balanced wye-wye system, the source is an abc-positive sequence set of voltages with Van- 120 20 Vrms. The per phase impedance of the load is 5 +j62. If the line impedance per phase is 0 Ω, find the line currents, the line to line voltages at the source, and the line to line voltages at the load 120 20 Vms 2. In a three-phase balanced wye-wye system, the source is an abc-sequence set of voltages with...
I. A balanced three-phase positive sequence wye-connected 60Hz source voltage has line-neutral voltage of V, 1000 V. It is connected to a three- phase wye connected load whose impedance is z 50+j37.7 2 a. Find line currents ia ib, ic and line-line voltages Vab, Vbo Vac b. Find the total complex power delivered to the load. c. Find delta-connected capacitor bank needed to bring the PF to 0.95 (lagging) of system. d. Re-calculate currents la, ib, io with Case c....
I. A balanced three-phase positive sequence wye-connected 60Hz source voltage has line-neutral voltage of V, 1000 V. It is connected to a three- phase wye connected load whose impedance is z 50+j37.7 2 a. Find line currents ia ib, ic and line-line voltages Vab, Vbo Vac b. Find the total complex power delivered to the load. c. Find delta-connected capacitor bank needed to bring the PF to 0.95 (lagging) of system. d. Re-calculate currents la, ib, io with Case c....
please solve as soon as possible, thank you.
Q3: For the following circuit, Z;=6+j9.2, Z=2+j112, ZL=2-310 S2, Vab= 90 cos(120xt+10°) V, Vbc= 90 cos(120t-110°) V, Vca= 90 cos(120xt+130°) V. Vbc Z, Fig. Q3: the circuit of Q3. a) Find the line currents I, I, and Ic. (15 marks) b) Compute the current through each voltage source, 11, 12, and 13. (9 marks) c) Find the reactive power produced by each voltage source in the delta configuration. (6 marks)
In a three-phase balanced wye-wye system, the source is an abc-positive sequence set of voltages with Van = 120 000 Vrms. The per phase impedance of the load is 5 +J60. If the line impedance per phase is 0 0, find the line currents, the line to line voltages at the source, and the line to line voltages at the load. 1. Van 120 0" Vrms ZY = 5+j Va VA neutral
(15 points) In a balanced three-phase wye-delta system, the source has a positive (abc) phase sequence and a phase voltage of Van 200VrmsZ - 30°. If the line impedance is zero and the line current is LaA -6ArmsZ- 65°, find the load impedance per phase in the delta. AB AB Arms
Note Unless otherwise specified, three phase systems are rated in terms of their line-to-line rms voltages So, for instance, a three-phase 230 kV transmission line has an rms phase voltage of 230/V3 kV. If you encounter a three-phase system specified with two voltages, e.g., 480/277 V, that implies that the line-to-line rms voltage is 480 V and the rms phase voltage is 277 v. Problem 8 The line-to-line voltage of a three-phase transmission line is Vbc-120 2.20° kV. Suppose the...
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