ANSWER:
1) Project c:
aw = x(a/p,i,n) + y + z(a/f,i,n)
aw = -500(a/p,6%,5) -50 + 120(a/f,6%,5)
aw = -500 * 0.2374 - 50 + 120 * 0.1774
aw = -118.7 - 50 + 14.088
aw = -154.612
2) Project d:
aw = p(a/p,i,n) + q + s(a/f,i,n)
aw = -1200(a/p,6%,infinity) -60 + 600(a/f,6%,infinity)
aw = -1200 * 0.06 - 60 + 600 * 0
aw = -72 - 60 + 0
aw = -132
so the annual worth of c is 154.612 and that of d is -132.
so we should select project d based on annual worth.
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