Convert the given integer number into its roman numeral equivalent between 1 and 3999. In PEP/8 assembly language.
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Translate the following C++ program to Pep/8 assembly language. Convert the given number into its roman numeral equivalent.class solution: def int_to_Roman(self, num): value = [ 1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1 ] symbol = [ "M", "CM", "D", "CD", ...
Convert this C++ language to PEP/8 assembly language. #include <stdio.h> int main(void) { int num, rem; printf("Enter a number: "); scanf("%d", &num); printf("Roman numerals: "); while(num != 0) { if (num >= 1000) // 1000 - m { printf("m"); num -= 1000; } else if (num >= 900) // 900 - cm { printf("cm"); num -= 900; } else if (num >= 500) // 500 - d { printf("d"); num -= 500; } else if (num >= 400) // 400 - cd { printf("cd"); num -= 400; } else if (num >= 100) // 100 - c { printf("c"); num -= 100; } else if (num >= 90) // 90 - xc { printf("xc"); num -= 90; } else if (num >= 50) // 50 - l { printf("l"); num -= 50; } else if (num >= 40) // 40 - xl { printf("xl"); num -= 40; } else if (num >= 10) // 10 - x { printf("x"); num -= 10; } else if (num >= 9) // 9 - ix { printf("ix"); num -= 9; } else if (num >= 5) // 5 - v { printf("v"); num -= 5; } else if (num >= 4) // 4 - iv { printf("iv"); num -= 4; } else if (num >= 1) // 1 - i { printf("i"); num -= 1; } } return 0;}
Translate the following C program to Pep/9 assembly language. #include <stdio.h> int main() { int number; scanf("%d", &number); if (number % 2 == 0) { printf("Even\n"); } else { printf("Odd\n"); } return 0; }
Translate the following C program to Pep/9 assembly language. #include <stdio.h> const int limit = 5; int main() { int number; scanf("%d",&number); while (number < limit){ number++; printf("%d",number); } return 0; }
Convert the following C fragment to equivalent MIPS assembly language Write mini calculator that take two integer numbers as input and ask the user if he need to compute addition, subtraction, remainder, division, or multiplication then print the result. Hint: you can give each operation a special number. For example, the addition (1), subtraction (2), …. And so on. The output must be something like: Enter the first integer number: 5 Enter the second integer number: 3 Which operation? 1...
NO PYTHON 8 CODE PLEASE.! it's PEP/8 the assembler, nothing to do with python. NO PYTHON 8 CODE PLEASE.! it's PEP/8 the assembler, nothing to do with python. NO PYTHON 8 CODE PLEASE.! it's PEP/8 the assembler, nothing to do with python. NO PYTHON 8 CODE PLEASE.! it's PEP/8 the assembler, nothing to do with python. NO PYTHON 8 CODE PLEASE.! it's PEP/8 the assembler, nothing to do with python. Write a program in Pep/8 or Pep/9 object code that...
Translate the following C program to Pep/9 assembly language. It multiplies two integers using a recursive shift-and-add algorithm. mpr stands for multiplier and mcand stands for multiplicand. A recursive integer multiplication algorithm #include <stdio.h> int times(int mpr, int mcand) { if (mpr == 0) { return 0; } else if (mpr % 2 == 1) { return times(mpr / 2, mcand * 2) + mcand; } else { return times(mpr / 2, mcand * 2); } } int main() { ...
Write the roman.cpp implementation file that converts a number entered in Roman numerals to a positive integer. Your program should consist of a class, say, romanType. An object of type romanType should do the following: Step a: Store the number as a Roman numeral. Step b: Convert and store the number as a positive integer. Step c: Print the number as a Roman numeral or positive integer as requested by the user. Step d: Test your program using the following...
Can someone code this asap? Use any language that you want.
2. Ancestral Names Given a list of strings comprised of a name and a Roman numeral, sort the list first by name, then by decimal value of the Roman numeral. In Roman numerals, a value is not repeated more than three times. At that point, a smaller value precedes a larger value to indicate subtraction. For example, the letter I represents the number 1, and Vrepresents 5. Reason through...
ranslate the following C program to Pep/9 assembly language. Note: Your jump table must have exactly four entries, but your program must have only three case symbols and three cases. #include <stdio.h> int main () { int guess; printf(“Pick a number 0..3: “); scanf(“%d”, &guess); switch (guess) { case 0: case 1: (printf (“Too low”); break; case 2: printf(“Right on”); break; case 3: printf(“Too high” ); } printf(“\n”); return 0; }