Question

Directions: Write the formula or name of the following compounds in the space provided. (Please note...

Directions: Write the formula or name of the following compounds in the space provided. (Please note that some of these compounds do not exist as a stable substance in nature, however the following should serve as a practice exercise in nomenclature.) If provided the name, then you must write the formula. If provided the formula, then you must write the correct name. Indicate IUPAC names only. NOTE: IF EVEN ONE PROBLEM IS LEFT UNANSWERED, YOU WILL RECEIVE ZERO (0) POINTS FOR THIS OPPORTUNITY. Use one of the following descriptions: ionic or covalent.

Compound Name   Formula Description

51. Tin (II) hypochlorite

52. Ammonium phosphate

53. Cs2SO3

54. CuNO3

55. Rubidium oxalate

56. Barium phosphide

57. Cobaltic hydrogen sulfate

58. N2O

59. Cesium phosphate

60. Stannic (IV) nitrite

61. Mercury (I) nitride

62. Hg2I2

63. Lead (II) hypochlorite

64. Oxygen

65. Ga(ClO4)3

66. Silver sulfate

67. MgF2

68. Copper (I) dichromate

69. Potassium iodate

70. Ferric oxide

71. Dinitrogen pentaphosphide

72. KMnO4

73. Lead (II) hypochlorite

74. Cupric sulfide

75. Rubidium sulfite

76. Calcium bicarbonate

77. Copper (II) chloride

78. Ammonium phosphide

79. Potassium oxalate

80. BiPO3

81. Co3P2

82. Ferric phosphate

83. In2O

84. Nitrogen dioxide

85. Lithium sulfite

86. CrBr3

87. Sodium carbonate

88. Iron (III) oxide

89. Chromium (VI) sulfide

90. Lead (IV) phosphide

91. HgF2

92. CaF2

93. Cadmium hypochlorite

94. Cobaltous nitrate

95. Cs2Cr2O7

96. NH4F

97. MnCO3

98. Tin (IV) nitride

99. Lithium nitride

100. Potassium chlorate

0 0
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Answer #1

8l. Cobalt I) phosphide FePoy 51.SnCctol2 (NHy)3 POy 53. Caesium sulgite Copper (I) nitorate Rb2CrOy) 56 BagP2 52. 82 83. IndSalts of alkali and alkaline earth metals are largely ionic in nature. In salts formed by transition metals, when Metal is in higher oxidation state then covalent character increases due to larger polarising power of cation. For example 89) CrS3  is covalent because Cr is in +6 oxidation state.

The procedure for writing formula is shown as:eg Ioon (TIL) Chlonide Fe31 Cr FeCl3

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