Question

Chapter 02, Problem 35 In an historical movie, two knights on horseback start from rest 89.9 m apart and ride directly toward each sther to do battle. Sir George's acceleration has a magnitude of 0.213 m/s2, while Sir Alfred's has a magnitude of 0.358 m/s2. Relative to Sir George's starting point, where do the knights collide? Number Units

Answer 1

2 Q A 2 L-d24d Cn 69.9 O 358 o 213

Answer 2

SOLUTION :

Let they collide after t secs. 

So,

Distance travelled by Sir George = 1/2 a t^2 = 1/2 * 0.213 * t^2 = 0.1065 t^2

Distance travelled by Sir Alfred = 1/2 a’ t^2 = 1/2 * 0.358 * t^2 = 0.179 t^2

As they collide, the sum of their distances travelled = 89.9 m

=> 0.1065 t^2 + 0.179 t^2 = 89.9

=> 0.2855 t^2 = 89.9

=> t^2 = 89.9 / 0.2855 = 314.8862

Sir George ’s distance travelled = 0.1065 * 314.8862 = 33.5354 m 

Hence,  their meeting  point is 33.54 m approx.  from the starting point of Sir George. (ANSWER).