In a historical movie, two knights on horseback start from rest 89 m apart and ride directly toward each other to do battle. Sir George's acceleration has a magnitude of 0.17 m/s2, while Sir Alfred's has a magnitude of 0.26 m/s2. Relative to Sir George's starting point, where do the knights collide
SOLUTION :
Let they collide after t secs.
So,
Distance travelled by Sir George = 1/2 a t^2 = 1/2 * 0.17 * t^2 = 0.085 t^2
Distance travelled by Sir Alfred = 1/2 a’ t^2 = 1/2 * 0.26* t^2 = 0.13 t^2
As they collide, the sum of their distances travelled = 89 m
=> 0.085 t^2 + 0.13 t^2 = 89
=> 0.215 t^2 = 89
=> t^2 = 89 / 0.215 = 413.9535
Sir George ’s distance travelled = 0.085 * 413.9535 = 35.19 m approx.
Hence, they collide at a point 35.19 m approx. from the starting point of Sir George. (ANSWER).
In a historical movie, two knights on horseback start from rest 89 m apart and ride...
In a historical movie, two knights on horseback start from rest 91 m apart and ride directly toward each other to do battle. Sir George's acceleration has a magnitude of 0.17 m/s2, while Sir Alfred's has a magnitude of 0.26 m/s2. Relative to Sir George's starting point, where do the knights collide?
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