Question

(a) What is the resistance (in ko) of a 6.00 x 10²0, a 2.40 kn, and 4.50 kn resistor connected in series? KO In a number (b) What is the resistance (In C) of a 6.00 x 10° 0, a 2.40 kn, and 4,50 kO resistor connected in parallel?

Answer 1

solution (a) Given't. R = 6x10² R₂ = 2.4kn R3 4.5 KB = 2.4x10² 4.5 x103 n how, for series conneetion & Req= R , + R2 &R Rear = (6X102) +(2.41103) + (4-5 490? In Req - (0.6x109) +(2-41109) + (4.5x109) Req= (0.6+2.4+ 4.5)*103 --(7.5 x 103 Req = [7.5 km a a Rea 2 now, for Parallel Connection: 1 ㅗ Rew t 1 R, * R2 wo T at pat Rear (0.60103 ) (0.6x103) (2.48103) (4.5x103) =) i Red -3 2 166x10 + 0.416x1013 + 0.22410-3

3 2.296 X10 xio - Rew Rear 3 = ) I 2.2 96 Xib Rew 435.54 2