12000 = 800 cos(a) * t
=> t = 15 / cos(a) .... (1)
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2000 = 800 sin(a) * t - 1/2 g t^2
2000 = 12000 tan(a) - 16 (225 / cos^2 (a) )
so 2000 = 12000 tan(a) - 3600 / cos^2 (a)
so 10 = 60 tan(a) - 18 / cos^2 (a)
divide by 2 , multiply by cos^2(a) you get :
5 cos^2 (a) = 30 sin(a) cos(a) - 9
=> 5cos^2(a) + 9 = 15 sin(2a)
if you solve this eqn you will get :
a = 70 degrees (check with calculator)
so option (D) is correct
the range of the projectile is maximum for an angle A = 45o
the range is
R = (u^2 x sin(2A)/g)
where u is initial speed of projectile and g = 9.8 m/s^2
please i need his asap A projectile is fired with an Initial velocity of 800 ft/s...
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