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Please respond both parts (ASAP)
month is normally distributed with a mean of $3000 and The average spending by middle-income family in a standard deviation 600. (Example 6, 268) 3+5 8 What is the probability that a randomly selected family in that income group will be spending less than $2670 a. b. Now, you randomly select 20 familles. What is the probability that a person spends more than $28702
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Answer #1

Given hod Von CoD PCwz 26%) 26T0- 3000 o0o b)PX 28 : p/Z > 2870-3000

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