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(1 point) Enter vector answers in terms of i and j. To enter the 0 vector,...
QUESTION 4 Given the equation of a point, r(t) ( I)i ( -I)j Sketch the graph of r(r) = (1 + l)i + (r2-Dj fr-2 2. Draw the (a) t 4 marks) position vector r(0) on the same diagram. b) Find the unit tangent vector of the point at 0 and show it on the same diagram in (a). Explain what you understand about the direction of the tangent (5 marks)
(1 point) (a) Show that each of the vector fields F-4yi + 4x j, G-i ЗУ x2+y2 x?+yi J, and j are gradient vector fields on some domain (not necessarily the whole plane) x2+y2 by finding a potential function for each. For F, a potential function is f(x, y) - For G, a potential function is g(x, y) - For H, a potential function is h(x, y) (b) Find the line integrals of F, G, H around the curve C...
(1 pt) Find a vector equation for the line through the point P = (1, -2, 3) and parallel to the vector v = (-3, 2, -3). Assume r(0) = li – 2 + 3k and that v is the velocity vector of the line.. r(t) = i + j+ Rewrite this in terms of the parametric equations for the line. X < N
(1 point) Given the acceleration vector a(t) = (-4 cos (2t))i + (-4 sin (2t))j + (-3t) k , an initial velocity of v (0) =i+ k, and an initial position of r (0)=i+j+ k, compute: A. The velocity vector v (t) = j+ . B. The position vector r(t) = j+ k
Calculus 4 Let f(x,y) = A)-i-j E) i+j 1. Find the gradient vector Vf (1, 1) at the point (x,y) = (1,1). B) - 1 - 1 D)-i-j 10. . Find the largest value of the directional derivative of the function f(x,y) = ry + 2ya at the point (3,y) = (1,2). A) 53 ' B) V58 C) V63 D) 74 E) 85 y + The function (,y) = 2 + y2 + A) (-3,5), saddle point C) (-1,3), maximum...
(1 point) Starting from the point (4,3,2)(4,3,2) reparametrize the curve r(t)=(4+3t)i+(3−3t)j+(2−2t)kr(t)=(4+3t)i+(3−3t)j+(2−2t)k in terms of arclength.
Problem 2: (0.2 point) The position vector, infeet, of an object follows a space curve defined by: r =e i[sin(t)+cos(t)j+cos(2t)k where t is time in seconds. Find the arc length of this space curve between 0 and 2 seconds 0.5- Be sure to clearly show the arc length integral Then use the trapezoidal rule with n 40 to approximate the arc length. Give your answer out to 3 decimal places. 0- You may use the tool of your choice to...
17 marks] Consider the functionf(x, y) = (y - 1) (x- 1). (a) Find a unit normal vector to the contour line given by f=0.5 at the point (x,y) (1.5,2). Do not forget to check that this point is on the contour line. (b) Consider the curve L given by r(t) = 2ti+3tj with 0 ts1 and the Cartesian basis vectors i= (1,0) and j= (0,1) of R2. Determine using the chain rule and use this result to determine all...
answer q5,6,7,8 please Find the unit tangent vector T(0) at the point with the gliven value of the parameter t. r(t)-cos(t)I + 8t1 + 3 sin(2t)k, t 0 T(o) Need Help? adHTer Find parametric equations for the tangent ine to the curve with the given parametric equations at the spedfled point. Evaluate the ietegral Need Help?h h SCakETS 13 200 Evaluate the integral. Find the unit tangent vector T(0) at the point with the gliven value of the parameter t....
(1 point) Starting from the point (-4,-1,0) reparametrize the curve r(t) = (-4+ 3t)i + (-1+2t)j + (0+2t)k in terms of arclength. r(t(s)) it j+ k