Question

keiko needs 100ml of a 5% acid solution for a science experiment. She has available a 1% solution and how many millikiters of the 6% solution should she mix to make the 5% solution

Answer 1

: Percent Quantity 1% - de 6% - 100.de 5% - 100 According to conditions - 18+ 6( 100-4e) : 51100) H + 600 -6 H = 500 -54 = 500-600 - 54 = -100 55 = 100 x= 100 - 20 H = 20 me of the des (100-20) = 80 ml of 67. Any Hence, 80 m millikiters of the 6%. solution should the mix to make the 5% solution.