Multiple questions , as per guideline only first one will be answered :
Solution: We have 1.5 L of 20% acid solution , we have to make it 23 % : how many ml. of pure acid should be added ?
This is volume/volume % solution.
20 % acid solution = 1500 ml
So, it was prepared by adding 300 ml of pure acid and 1200 ml of water.
so total volume of 23 % (v/V) acid solution = 100/77 * 1200 = 1558.45 ml
So to obtain 23 % solution from 1.5 L of 20% acid solution , ml. of pure acid needs to be added :
1558.45 ml - 1500 ml = 58.45 ml of Pure acid.
How many mL of pure acid needs to be added to 1.5L of 20% solution to...
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