The complete cell recation is as follows:
Sn + 2Ag+ -----> Sn2+ + 2Ag(s)
E°cell=E°+E°
Sn(s) ---> Sn2+ +2e- = +0.14
Ag+ + 2e- ---> Ag(s) =+0.79
E°cell= 0.93 V
now we can determine the Ecell as follows:
Ecell = E°cell - (RT/nF)ln(Q)
R=8.3145 J(/mol)(K)
T= 25C or 298K
n= 2 (2e-)
F= 96,485 c/mol ( F is a constant)
Q= products/reactants
= (0.0155)/(3.50)^2
Q= 1.26*10^-3
Now put all the values in the following equation:
Ecell = E°cell - (RT/nF)ln(Q)
Ecell= 0.93- 8.3145(298)/2(96,485)ln 1.26*10^-3
Ecell= 0.93+ 0.085
Ecell= 1.015 V
Now calculate the G°rxn as follows:
G°rxn = -nFE°cell
G°rxn = -2(96,485)(0.93)
G°rxn = -179462.1 J/mol or -179.5 KJ/ mol
Grxn = -nFEcell
Grxn = -2(96,485)(1.015)
Grxn = -195864.55J/mol or -195.86 KJ/mol
I have figured out everything except the two delta G with the red x's by them....
For the following electrochemical cell Sn(s)|Sn?(aq, 0.0155 M)lAg (aq, 2.50 M)JAg(s) write the net cell equation. Phases are optional. Do not include the concentrations. Calculate the following values at 25.0 ℃ using standard potentials as needed Number Number kJ/ mol cell Number Number &Grin- kJ/ mol cell