Question

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(1 point) The figure below gives the behavior of the derivative of g(x) on -2 < x < 2. Graph of g'(x) (not g(x)) (Click on the graph to get a larger version.) Sketch a graph of g(x) and use your sketch to answer the following questions. A. Where does the graph of g(x) have inflection points? x= 1 Enter your answer as a comma-separated list of values, or enter none if there are none. B. Where are the global maxima and minima of g on (-2,2]? minimum at x = 1 maximum at x = C. If g(-2) = 3, what are possible values for g(0)? g(0) is in (Enter your answer as an interval, or union of intervals, giving the possible values. Thus if you know -1 <80) < 4, enter (-1,4). Enter infinity for interval [-1,-1) to indicate a single point). the How is the value of g(2) related to the value of g(0)? 8(2) 1 8(0) (Enter the appropriate mathematical equality or inequality, =, <, >, etc.)

Please try to explain, clearly as possible.

Answer 1

graph of ger) taotlo - 2

inflection at c=1 as 9"x) = 0 elope of g')) 9. x=2 &x=-2 arl ceuticalpt off as & g'() = 0 (b) global maxima will occure at x=2 as g(x) is increasing evensince lieg'@) is always positive global minima will occure at x=2 as aften g (2) to value af g (c) will increase as g'> for > - 2 (c) 962) -3 yet& (X) 96) = 9+2) + aura under g'a) from x=-2 to x=0 how even graph is not clear to give exact amea so allwe know is Celse calculate go) g(2) from graph) Cassunning ABC so glo) > 3 as a retough selleledel solo triangle

ge) > 30 as 9') >0 for x E[-2, 2] so 96) is always juceeasing with incuease inac
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