Question

If the second side of a triangle is 5 more than the first and the third side is 3 less than twice the first, how long is each side if the perimeter is 42ft?

First side:

second side:

third side:

Answer 1

Let the first side bex.ft Given second side of a triangle is 5 more than the first Then second side is 32+5) ff and thired side is 3 less thani twice the first then thired side = (2x - 3) ft Given perimiter is 42 ft i.e u + (+5) + (2x-3) = 42 44+2 2 = 42 => 42=40 n =.10 ft =loft first side second side thired side a (10+5) = 1541 (2x10-3) = 17 ft