An electron is launched at 45° at a speed of 2.5 x 106 m/s from the positive plate of a parallel-plate capacitor
An electron is launched at 45° at a speed of 2.5 x 106 m/s from the positive plate of a parallel-plate capacitor as shown in the figure below. The electron lands d = 4 cm away.
What is the electric field strength inside the capacitor?
(Please give your answer in N/C with at least two significant figures; e.g. 2700).
Homework Answers
Range, R = u^2 sin(2 theta)/a
0.04 = (2.5 x 10^6)^2 sin(2 x 45)/a
Acceleration, a = 1.56 x 10^14 m/s^2
Acceleration, a = qE/m
1.56 x 10^14 = 1.6 x 10^-19 x E/(9.1 x 10^-31)
Electric field, E = 888.67 N/C
Comment in case any doubt please rate my answer.....
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An electron is launched at 45° at a speed of 2.5 x 106 m/s from the positive plate of a parallel-plate capacitor
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Express your answer with the
appropriate units.
What is the smallest possible spacing between the plates?
Express your answer with the appropriate units.
An electron is launched at a 45? angle and a speed of 5.0×106m/s from the positive...
An electron is launched at a 45? angle and a speed of 5.0×106m/s
from the positive plate of the parallel-plate capacitor shown in
the figure (Figure 1) . The electron lands 4.0 cm away.
A)What is the electric field strength inside the capacitor?
Express your answer with the appropriate units.
B) What is the smallest possible spacing between the plates?
Express your answer with the appropriate units.
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Question 2 45° In the figure above, an electron is released at 4.95x106 m/s and at an angle of 4:5 degrees from the parallel-plate capacitor's positive side. If the electron lands at a distance of 1.00 cm away, what would be the strength of the electric field within the capacitor?
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part a: answer is 4053.6 N/C.
**JUST NEED HELP WITH PART B**
Part B: Find the speed of the electron when it exits
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Please show full work and drawings step by step I will rate you thumbs up Henry...
Please show full work and drawings
step by step I will rate you thumbs up
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An electron is launched at a 45? angle and a speed of 5.0×106m/s
from the positive plate of the parallel-plate capacitor shown in
the figure(Figure 1) . The electron lands 4.0 cm away.
What is the electric field strength inside the capacitor?
Express your answer with the
appropriate units.
What is the smallest possible spacing between the plates?
Express your answer with the appropriate units.
An electron is launched at a 45? angle and a speed of 5.0×106m/s
from the positive plate of the parallel-plate capacitor shown in
the figure (Figure 1) . The electron lands 4.0 cm away.
A)What is the electric field strength inside the capacitor?
Express your answer with the appropriate units.
B) What is the smallest possible spacing between the plates?
Express your answer with the appropriate units.
both parts pls
Review Part A An electron is launched at a 45 angle and a speed of 5.0x 106 m/s from the positive plate of the parallel-plate capacitor shown in the figure (Figure 1). The electon lands 4.0 cm away. What is the electric field strength inside the capacitor? Express your answer with the appropriate units. Value Units Submit Part B What is the smallest possible spacing Express your answer with the appropriate units between the plates? Figure く...
Question2 45 In the figure above, an electron is released at 4.15x106 m/s and at an angle of 45 degrees from the parallel-plate capacitor's positive side. If the electron lands at a distance of 4.60 cm away, what would be the strength of the electric field within the capacitor?
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Question 2 45° In the figure above, an electron is released at 4.95x106 m/s and at an angle of 4:5 degrees from the parallel-plate capacitor's positive side. If the electron lands at a distance of 1.00 cm away, what would be the strength of the electric field within the capacitor?
The figure shows an electron entering a parallel-plate
capacitor with a speed of 5.4*10^6 m/s. The electric field of the
capacitor has deflected the electron downward by a distance of
0.618 cm at the point where the electron exits the capacitor.
part a: answer is 4053.6 N/C.
**JUST NEED HELP WITH PART B**
Part B: Find the speed of the electron when it exits
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Review The figure shows an electron entering a parallel-plate capacitor with a speed of...
An electron is released from rest at the negative plate of a
parallel plate capacitor and accelerates to the positive plate (see
the drawing). The plates are separated by a distance of 1.7 cm, and
the electric field within the capacitor has a magnitude of 2.7 x
106 V/m. What is the kinetic energy of the electron just as it
reaches the positive plate? The figure shows a vertical plate on
the left that is negatively charged and another vertical...
Please show full work and drawings
step by step I will rate you thumbs up
Henry Ford College/ Physics 232-12 Summer 2018 Problem 2 (30 points) An electron is launched at a 45 angle and a speed of s.0x 10 m/s from the positive plate of the parallel-plate capacitor shown in Figure 2. The electron lands 4.0 cm away. 6 What is the electric field strength inside the capacitor? What is the smallest possible spacing between the plates? a. b....
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