Question

The stiffness of springs AB and CB is k₁ lb/ft. The original length of spring DB is l₁ ft and its stiffness is k₂ lb/ft. Calculate the stretch and the force in springs CB and AB when the stretched length of spring DB is l₂ ft. Write the equilibrium equation in the x direction and calculate the force F.

12 ft F=? lb

l₁ = 1.3 ft

l₂ = 4.6 ft

a = 3.2 ft

k₁ = 2.3 lb/ft

k₂ = 4.7 lb/ft

A) The stretch in spring BD. (ft)

B) The stretch in spring BC and BA. (ft)

C) The force in spring BD. (lb)

D)The force in spring BC and BA. (lb)

E)The force F applied by the worker. (lb)

Answer 1

ec SA @sveta in Ec , wetch h, BA Se hosp t 2.151 446+3.1