Question

10. A hinged rigid bar of length/ is connected by two springs of stiffnesses k1 an and is subjected to a force F as shown in
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Ds ル Jレ 山 Lon(B) .ng:d 版 The Porly dr attachemnly 4-gnngx 1く,a.dkL and.HuPon- alun 야.ttu Force F undego lanie) (ONHo3nkl. Ahou lheu 山

Add a comment
Know the answer?
Add Answer to:
10. A hinged rigid bar of length/ is connected by two springs of stiffnesses k1 an and is subjected to a force F as...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A hinged rigid bar is connected by two springs of stiffnesses kı and k2 and is subjected to a for...

    A hinged rigid bar is connected by two springs of stiffnesses kı and k2 and is subjected to a force F applied at 'D' as shown in the figure. Assuming that the angular displacement of the bar is small (sin θ-6), find the equivalent spring constant of the system that relates the applied force F to the resulting displacement x. 1. ki A hinged rigid bar is connected by two springs of stiffnesses kı and k2 and is subjected to...

  • A rigid beam CBDA is hinged at A and supported by two springs at C and...

    A rigid beam CBDA is hinged at A and supported by two springs at C and B with a vertical load 'P' at point D as shown in the given figure. The ratio of stiffness (k2/k1) of springs at B and C is 2. The ratio of forces in spring at C to that at B is k, k2 0.5 m (a) 3/4 (c) 4/3 (b) 1 (d) 2

  • The stiffness of springs AB and CB is k1 lb/ft. The original length of spring DB...

    The stiffness of springs AB and CB is k1 lb/ft. The original length of spring DB is l1 ft and its stiffness is k2 lb/ft. Calculate the stretch and the force in springs CB and AB when the stretched length of spring DB is l2 ft. Write the equilibrium equation in the x direction and calculate the force F. l1 = 1.3 ft l2 = 4.6 ft a = 3.2 ft k1 = 2.3 lb/ft k2 = 4.7 lb/ft A)...

  • Newton's Third Law (two springs) Two springs with spring constants k1 = 24.6 N/m and k2...

    Newton's Third Law (two springs) Two springs with spring constants k1 = 24.6 N/m and k2 = 15.6 N/m are connected as shown in the Figure. Find the displacement y of the connection point from its initial equilibrium position when the two springs are stretched a distance d = 1.3 m as a result of the application of force F 0 0.824 m Use Newton's first law and apply it to the connection point! Submit Answer Incorrect. Tries 1/6 Previous...

  • 1. Springs and a mass are attached to a rigid bar, as shown in Fig 1....

    1. Springs and a mass are attached to a rigid bar, as shown in Fig 1. The hinges are free to rotate. 0 denotes the rotational angle of the rod, and 0-0 when all springs are not stretched. The mass of the bar and the size of the mass are negligible. Neglect gravitational force, and assume 0 is very small. 1) Derive the equation of motion for this system with Lagrange's method. (20pt) 2) Find the natural frequency of the...

  • Three rigid bodies (Nodes 2, 3, and 4) are connected by five springs as shown below....

    Three rigid bodies (Nodes 2, 3, and 4) are connected by five springs as shown below. Assume that the bodies can only undergo translation in the horizontal direction. Horizontal force P2=1000 N and P4=1500 N is applied to Elements 2 and 4, respectively. The spring constants in (N/mm) are given as: k1=400, k2=500, k3=600, k4=100, and k5=300. Nodes 1 and 5 are fixed. Determine the nodal displacements and reaction forces at the walls. Problem 1. (3 points) Three rigid bodies...

  • 2. Consider the system shown in the figure below, comprised of the same motor, steel beam,...

    2. Consider the system shown in the figure below, comprised of the same motor, steel beam, steel cable and crate All assumptions and properties are the same with one exception; the cable is no longer considered as rigid Cable properties: length = 4 m, diameter = 0.007 m, E = 207 GPa, Calculate the equivalent stiffness of the cable, in units of N/m. (See table 4.1.1 in your textbook) Draw an equivalent system diagram where the beam and cable each...

  • UIT LE 11/4., /4.127 Three rigid bars with the same length L are pinned as shown...

    UIT LE 11/4., /4.127 Three rigid bars with the same length L are pinned as shown in the figure. They are connected by linear springs with the same spring constant K. A downward force P is applied at the point F. Use the principle of virtual work to determine the vertical displacements at points A, C, and F corresponding to the equilibrium state. Assume that all displacements are small at the equilibrium state.

  • *Computer-Oriented Problems* 3/285. The two 0.2-kg sliders are connected by a light rigid bar of length...

    *Computer-Oriented Problems* 3/285. The two 0.2-kg sliders are connected by a light rigid bar of length L = 0.5 m. If the system is released from rest in the position shown with the spring unstretched, plot the speeds of A and B as functions of the displacement of B (with zero being the initial position). The 0.14-MPa air pressure acting on one 500=mm^2 side of slider A is constant. The motion occurs in a vertical plane. Neglect friction. State the...

  • The two uniform bars are identical. The mass and length of each bar are m= 30...

    The two uniform bars are identical. The mass and length of each bar are m= 30 kg and L=1.6 m. The top bar rotates around point A, coordinate , locates the bar, and force F(t) = 500 sin 60t (in N) is being applied to the end of the bar. A spring with k = 10000 N/m connects the top bar to a fixed point. The bottom bar rotates around its center at point B and coordinate 0g locates this...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT