Question

(2) You live in an old town that doesn't follow an orthogonal grid. Instead, one set of streets is parallel to a river (generally NW-SE, but not exactly) while the other set of streets is parallel to the lake front where the town was founded (generally NE-SW, but not exactly) and the blocks are elongated diamonds. You and your friend live on Cedar Lane, so when you walk home you each walk a distance A down 28th Street and then turn in opposite directions to walk home when you reach Cedar. Both of your houses are the same distance B from 28th, and you know your house is exactly N times as far from school as the crow flies from your friend's. What is the angle between the numbered streets (e.g., 28th) and the named streets (e.g., Cedar)?

Answer 1

House Q. As given in School the e question: sus the school. - (1) sos' in 28th Street. - (2) i Pop' in CEDAR Lane. - (3) ; • We have to find the angle & between CEDAR Lave and | 28th Street CEDAR K 28th Street Lane Now, so = A } from given question, Op=op' =B we walk distance A from school, then go distance B in opposite direction. Distance of school from I p = My House my house ; - p'>My friend's SP= 5 ArtB² - ZAB Caso House . and from my friends house :- Sp'= TartB² - 2 AB (as (180°-o) - JA78+ 2AB (oso According to the problem of my house is N times for than my → N.SP = sp frient's house] N ato + 2AB COSS -sarto - 2AB Caso NA (AEB) - (A^26) = – N²2AB COSO - LAB lose

.. (N+1) 248 Cos 0 - (AFS) [i-wy Hence, the probleem is solved. Here, N can be anything, even ser 1 [ this case is shown in the picture As, in the picture shown, my house is actually closer to school.. than drawn). on UN IN