Consider system that is vibrating in the vertical direction due to the rotating unbalanced mass as...
For the vibrating system shown in Fig. 3, a mass of 5 kg is placed on mass m at t = 0 and the system is at rest initially (at t = 0). Given that m = 20 kg, k = 600 N/m, and c = 60 Ns/m. Plot the response curve x(t) versus t using MATLAB. 3 kg m Fig. 3
The system parameters of a freely-vibrating damped SDOF system are as follows: Mass, m= 100 kg Damping Factor, c = 200 kg/s Spring Stiffness, k = 3000 N/m Initial Position, x, = 1 m Initial Velocity, v,= 0 m/s a) Create a MATLAB code and using the specified system parameters compute (using the correct units) the system characteristics: 1) natural (circular) frequency on; 2) cyclic frequency fn; 3) cyclic period p; 4) damped natural (circular) frequency 0g, and 5) damping...
solve by matlab The damping system has a single degree of freedom as follows: dx2 dx mo++ kx = F(t) dt dt The second ordinary differential equation can be divided to two 1sorder differential equation as: dx dx F C k xí -X2 -X1 dt dt m m m = x2 ,x'z m N F = 10, m = 5 kg k = 40, and the damping constant = 0.1 The initial conditions are [00] and the time interval is...
QUESTION 6 130 MARKS For a vibrating system, the body mass is 10 kg, stiffness is 2.5 kN/m, and damping constant is 45 Ns/m. A harmonic force of amplitude 180 N and frequency 3.5 Hz acts on the mass. If the initial displacement and velocity of the mass are 15 mm and 5 m/s, compute the complete solution representing the motion of the mass. 45 (30 Marks) QUESTION 6 130 MARKS For a vibrating system, the body mass is 10...
Problem 2. Eigenvalue and Eigenvector Consider the mass-spring system in Fig. P13.5. The frequencies for the mass vibrations can be determined by solving for the eigenvalues and by applying Mi + kx = 0, which yields m 0 07/31 (2k -k -k X1 (0 0 m2 0 {2}+{-k 2k -kX{X2} = {0} LO 0 m3] 1 iz) 1-k -k 2kJ (x3) lo Applying the guess x = xoeiat as a solution, we get the fol- lowing matrix: 52k - m102...
Mass-String-Damper system: The molecular bond due to intermolecular forces is flexible. A diatomic molecule like oxygen (O_2), if disturbed, will oscillate to and fro the equilibrium position ( minimum potential energy) approximated by the equation: mu d^2x/dt^2+kx=0 Where mu is the reduced mass of the system mu = m_02 / 2 and k is the spring constant. The mu for the Oxygen molecule (O_2) is 1.33 x 10^-26 kg and k =1195 N/m. What is the natural frequency of O_2...
Solve it with matlab 25.16 The motion of a damped spring-mass system (Fig. P25.16) is described by the following ordinary differential equation: d’x dx ++ kx = 0 m dr dt where x = displacement from equilibrium position (m), t = time (s), m 20-kg mass, and c = the damping coefficient (N · s/m). The damping coefficient c takes on three values of 5 (under- damped), 40 (critically damped), and 200 (overdamped). The spring constant k = 20 N/m....
For the spring-mass system shown below with the mass sliding on a frictionless floor, A = 1.0 m, the spring constant k = 2.0 N/m, and the mass m = 2.0 kg. The period of oscillation T is QUESTION 18 For the spring-mass system shown below with the mass sliding on a frictionless floor, A = 1.0 m, the spring constant k = 2.0 N/m, and the mass m = 2.0 kg. The period of oscillation T is x= 0...
using matlab The damping system has a single degree of freedom as follows: dx2 dx m++ kx = + kx = F(t) dt dt The second ordinary differential equation can be divided to two 1st order differential equation as: dx dx F с k x1 = = x2 ,X'2 X2 -X1 dt dt m m m m N F = 10, m = 5 kg k = 40, and the damping constant = 0.1 The initial conditions are [0 0]...
1- Consider a spring mass system shown below with K = 8N/m and m= 9kg. It's not given intial conditions X, = 2 m und = 4m/s 4 W- m * Calculate graph s(t) for two full period (label ases] Calculate and ~ Calculate vct) "Caclate alt) - Vibration dynamics