Question

Someone please help me with this question. I am STRUGGLING with it! Their are four parts to it!

Conservation of momentum [7] Conservation of energy [8] Where the prime represents the final velocities. These two equations simplify to [9] Note that the initial speed of the plastic, Vplastic = 0. In part I, you found that the speed and momentum of the steel ball at the bottom of the ramp are 1.38 m/s and pi = 3.141592653589793 msteelvsteel = 0.0367 kgm/s respectively. By substituting Equation [9] into [7], the speeds of steel and plastic balls after the collision can be determined. Simplifying gives [10] The speed of the steel ball after collision is then [11] What is the speed of plastic ball after the collision? Use Equation [10] to calculate the speed of the plastic ball. The mass of the steel ball is 26.7 g and that of the plastic ball is 10.7 g. ____ m/s Submit Answer Incorrect. Tries 1/5 Previous Tries What is the speed of steel ball after collision? Use Equation [11] to calculate the speed of the steel ball. ____ m/s Submit Answer Incorrect. Tries 0/5 Now since we also know the time it takes for the steel and plastic balls to fall to the floor, we can calculate the horizontal distance traveled by each ball. The time taken to fall is determined earlier to be 0.2655 s. What is the horizontal distance traveled by the plastic ball after the collision? Note the units for the distances. ____ cm Submit Answer Incorrect. Tries 0/5 What is the horizontal distance traveled by the steel ball after collision? ____ cm

Answer 1