Question

In each part below a function p and a function f are given. Treat p as a parent function and identify the horizontal graph transformation(s) which take the graph of y = p(x) to the graph of y = f(x). (A.) p(x) = (x and f(x) = (x+1 (B.) p(x) = (x and f(x) = 2x (c.) p(x) = x2 and f(x) = (x + 3)2 (n.) p(x) = x2 and f(x) = 4x2 – 16x + 16 (E.) p(x) = ** and f(x) = x2_6x+9 (F.) p(x) = ln(x) and f(x) = ln(x-3) (G.) p(x) = ex and f(x) = e 0,5x (H.) p(x) = ex and f(x) = 5* (1.) p(x) = ex and f(x) = é (5.) p(x) = { and f(x) = x 24 (K.) p(x) = xi and f(x) = 2xi
（B）and（C）

Answer 1

bees (B.) peal = 5x solution. There compression and f(x) = Jan is a horizontal f(x) = 2x by in

a factor of E ve - To plot y = 5x we put different values of x to get different values of y 3) put x = 1 we get y = 1) = put x=2 we get y = 152 » put x = 3 up we get y = 113 put x = 4 we get y = [2] می) To plot y = √2x we put different values of x to get different values of

» put x=1 put X=2 put: x=3 put x=4 get y = 52 we get y = 2 we get y =56 we get y = 58. -

Ques (0) Pra ya and f(x) = (x+3)2 Solection! There is a horizontal shift of 3 unit to the left in graph 2 f(x) = (x+3) * To plot values of x y = to x² put different get different values

> put x = 1, y = (?=0 3 put x = 1, y = (2)2 = 9 5 put X=-1, y = 61*=D =) put x = -2, y = (-2)=19 To plot y = (x+3)? put different values of x to get different values of y 2 =put X =0 we get y = 10+3) = 9 put x=-1 we get y = (-1+3) = 4 put x=-2 we get y = (-2+3) = 1 put x = 1 we get y = (1+3) = 16 uve

- = (x+3y- НА 1,16) че