Question

a 40 70 + 10 3. Power Dissipated in a Resistor Simplify the circuit using a delta-to-wye transformation and then calculate the power dissipated in the 5 2 resistor. 6V b с 20 502

Answer 1

o given Tor 42 mm RC + GV 22 > as 4472 1л are is delta Loop so convert into star 4X7 RA - 2-333 s 4+HI Ах RB 0.333 . 4+7+1 RC= 1x7 0.583 r 4+HI

is Now Circuit the 2.333 2 20.583 + GV 0.333 52 2r at v apply Nota analysis V-0 V-0 =0 + 2+0.333 5+0.583 2:333 6. + + va 2.333 5.583 2.333 2-333 1.03638 V = 2.57146 V=2.481 Volt

Now Isra V-0 $+0:583 2.481 Isa 5.583 Iso = 0.444 Amp Psa= (Ise) x 5 Psa= (0.444) * X5 Pse = 0.9873 Watt