Question

Without using a calculator, enter the correct value of 5-2 Express your answer to three significant figures or as a fraction. Radioactive substanoces follow a specific law of decay. Namely, if you have a sample of some radioactive isotope, the quantity left after a certain time, called the half-life and denoted 71/2 onehalf of what you had initially. If you wait a second hai-ife, then there will be half of what was left at the end of the first half-life. Since 1/2-1/2-1/4, you will have one-fourth of the original quantity left after two half lives. You can continue with this procedure to find the fraction of the original sample that hasnt decayed after any number of half-lives. However, this would become quite cumbersome if you are interested in the quantity left after, say, 10 half-lives. In this case, the quantity you are looking for would be found by muiltiplying the original quantity 5-2 = 4.00x10 V Correct To solve this problem, we use exponents. An exponent, a small number wnitten above and to the right, tells you how many copies of a particular number are multiplied together. In our example, where the original quantity of radioactive isotope must be multiplied by 10 factors of 1/2, you can write the multiplication in a more compact way If you initially had N atoms of some radioactive isotope, then after three half-lives, you would have N (1/2) atoms left. After another two half-lives, you would have N (1/2) (1/2) atoms left Saying Tirst three, then two more doesnt affect the fact that you have undergone a total of five half-lives, so equally valid would be to say that at the end of these two periods you have N (L/2) atoms left. Setting the two expressions equal .e, N(1/(1/2)N(/2) mustrates an important rule about exponents: Multiplying the same number to two diflerent exponents is equal to raising that number to the sum of those exponents. After dividing the N out of our example, we see that Of course, s + 2 5, so you can see the rie in erect. Using 1:2 as our base, the rie can be written generally as Part C Which of the following are equivalent to (1/2) Check all that apply. 47-4 Submit

0 0
Add a comment Improve this question Transcribed image text
Answer #1

part C)
1st and 3rd options are correct.

because
1st option) (1/2)^3*(1/2)^5 = (1/2)^(3 + 5)

= (1/2)^8


3rd option) (1/2)^2*(1/2)^3*(1/2)^3 = (1/2)^(2+3+3)

= (1/2)^8

Add a comment
Know the answer?
Add Answer to:
Without using a calculator, enter the correct value of 5-2 Express your answer to three significant...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A) According to the data, what are the approximate half-lives of the hypothetical elements A, B,...

    A) According to the data, what are the approximate half-lives of the hypothetical elements A, B, C, and D? B) Which of the hypothetical substances would be the most harmful to living organisms? Why? C) What part of an original isotope's number of atoms remains after two half-lives? D) After three half-lives of an isotope, 1 billion (one-eighth) of the original isotope's atoms still remain in a certain amount of this element. How many atoms of the daughter product would...

  • 3 pts It is handy to have an equation to quickly determine the number of atoms...

    3 pts It is handy to have an equation to quickly determine the number of atoms left in a radioactive sample as a function of time. For this we can divide the initial amount by two for every half-life of time, the following equation does exactly that: N No (24/01/2) N, 2 1/2 where N is the initial number of atoms at t=0, t is time passed and is the half-life. Use the above equation to help you answer the...

  • Using Python 3... Question 4: Carbon dating (3 points) Archaeologists use the exponential, radioactive decay of...

    Using Python 3... Question 4: Carbon dating (3 points) Archaeologists use the exponential, radioactive decay of carbon-14 to estimate the death dates of organic material. The stable form of carbon is carbon-12, and the radioactive isotope carbon-14 decays over time into nitrogen-14 and other particles. Carbon is naturally in all living organisms, and the carbon-14 that forms in the upper atmosphere enters into living things as long as they are taking in material (food, air, etc.) that contains carbon. We...

  • (c) Compare your answers to (a) and (b), and explain this behavior. 6. The lifetimes of...

    (c) Compare your answers to (a) and (b), and explain this behavior. 6. The lifetimes of radioactive nuclei are independent and exponentially distributed. The half-life is given by t1/2 = ln2/λ, where t1/2 is the time such that the expected fraction of atoms remaining is 1/2. (a) Iodine-131 is radioactive, with a half-life of 8.02 days. What is the probability that a single atom of Iodine-131 is still un-decayed after 30 days? (b) How long do you have to wait...

  • 1.Describe what happens to a carbon-11 atom when it undergoes positron emission. The decay of a...

    1.Describe what happens to a carbon-11 atom when it undergoes positron emission. The decay of a carbon-11 atom _____(options;changes a nuetron into proton, changes proton into neutron, is hit with a neutron, reconfigures its protons and neutrons) and this causes it to emit______(options; a negatively charged electron sized particle, a positively charged electron sized partticle, two atoms and several neutrons, two neutrons and two protons) 2.An atom undergoes radioactive decay according to this equation: ___. What is the identity of...

  • number 1 thank you. this copy of the exam at home. You are free to use your textbook and notes while completing the...

    number 1 thank you. this copy of the exam at home. You are free to use your textbook and notes while completing the exam. You MUST turn in the completed retake by the due date above, no credit will be given if even one day late. The score for this retake will be averaged with your in-class exam score for your final Exam 2 score. 1. (4 pts) Assume nwaccium is a radioactive element that decays into another element over...

  • I have a test tomorrow and really need help seeing how to do numbers 1,2,3 and...

    I have a test tomorrow and really need help seeing how to do numbers 1,2,3 and 4. If you can start with telling me what equation to use, then solving using that equation, it would be much appreciated. facweb.bhc.edu Practice Kinetics Solve the following use appropriate units and sig figs. QUESTIONS Half lives and rate constants 1. Calculate the first-order rate constant for the radioactive decay of radium. The 1590 years. 2. Calculate the rate constant for the decay of...

  • Review | Constants Periodic Table In the parts that follow, use the following abbreviations for time...

    Review | Constants Periodic Table In the parts that follow, use the following abbreviations for time If a substance is radioactive, this means that the nucleus is unstable and will therefore decay by any number of processes (alpha decay, beta decay, etc.). The decay of radioactive elements follows first-order kinetics. Therefore, the rate of decay can be described by the same integrated rate equations and half-life equations that are used to describe the rate of first-order chemical reactions: Measure of...

  • what is the answer of 12 and 13 estimated as equivalent to that released by 20.000...

    what is the answer of 12 and 13 estimated as equivalent to that released by 20.000 tons of TNT. Assume 200 MeV is released when a 235 U nucleus absorbs a neutron and fission that 3.8 x 10' J is relensed during detonation of 1 ton of TNT. nuclear fissions occurred at Hiroshima, and what was the total de mass? utron and fissions and of 1 ton of TNT. How many was the total decrease in Scanned by CamScann 1.9...

  • The Fukushima nuclear reactor accident caused the environmental release of significant amounts of radioactive caesium (Cs)...

    The Fukushima nuclear reactor accident caused the environmental release of significant amounts of radioactive caesium (Cs) isotopes. Specifically, caesium-134 and caesium- 137, which have half-lives of, respectively, two years and 30 years. The survey of soil radioactivity conducted in June 2011 revealed soil surface Cs-134 activity of about 500,000 Bq/m2 in the town of Okuma (roughly 10 km from the stricken power plant) and Cs-137 activity of roughly the same level. Disregarding any other changes or cleanup efforts since then,...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT