Question

A ball is thrown with an initial velocity, V, of 160 ft./sec, directed at an angle, 0, of 53° with the ground. (a) Find the x and y components of vo. (b) Find the position of the ball and the magnitude and direction of its velocity when t = 2 seconds. (c) At the highest point of the ball's path, what is the ball's altitude h, and how much time has elapsed? (d) What is the ball's range d? (see figure)

Answer 1

66.29 V = 160 ft/s 8=53° (a) Vox = 160 coss3°= 96.29 ft Is Voy - 160 sm 53° = 127.78 ft/s (b) Vy = Voy - gt = 127.78 28 (2) = 63.38fts x= vox = 96.29 ftis Direction of velouty - tant (vy) = tant (63.38) = 33.3540 with horizontal Magnitude of velouty = Jug?tu2 = 596.292 +63.882 = 115.277 HIS x=vata (96.29) (2) = 192.58ft y = vyt - 2 gt² = (127.78) (2) - 32.2 ( 4 = 191.16 H Position = (192.58 ft, 191016 ft)

(c) At highest point, - vya voyat > t - 127.78 -13.969 32.2 Vo?sm?o = 1602 xsm? 53° – 253,5444 29 2 x32.2 (d) d = v. ² sim 20 = 1602. x sim (1060) 22 . 2 d = 764.23 ft)