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#3 cannot use Cd(NH3)42+ or any cadmium salt

CdC2O4(s) + 4 NH3 (aq) ←→ Cd(NH3)4+2 (aq)-C204-2(aq) Note: C2o2(aq) is the oxalate ion 1. If solid CdC204(s) is added, the equilibrium will a. shift toward the reactants b. shift toward the products c. not shift at all d. produce some of the solid. 2. If NH3(aq) is added the equilibrium will a. shift toward the reactants b. shift toward the products c. not shift at all d. cause some solid to be formed 3. List a solution (that does not contain oxalate ion) which when added will cause th equilibrium to shift to the left to form some solid CdC204. Explain how your choice causes CdC204 to be formed

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