Question

• Write your name on your answer sheet. Show all the work done to solve the problem. • Hint: It is a straight forward probleme, redraw simplify the cicuit as needed. and 35- teo A The switch in the wicuit has been clared for a long time and opens at t=o. Find the inductor curent ilt) and the voltage volt) for too. 24 A

Answer 1

32 mo 14 I J 1 Ve 2460 342 Given theet swriten is closed fees tco and opened for to at t=0 ..ter tco, cicut is drawnas, wMzsz 24A 3401 32. Ve Since circuit is closed from long time, incluctoris in stedy state and is this short circuited Thus equivalent circuit for tco is drawn as

mizu vezan 24A ma 4 assuming B to be reference node applying nodel Analysis at node A, 24 - VA - UB + VA-VB 4 2 0 32 is short ciented, no worrent flows through it 3. Vo is seeference, VB-OU .: 245 VA VA => VA# QUA = 24 A VAS 4 x 24 V => Na=320 .. I-VA 5* I16 A 5. cweest thoough in ductor to tzo, I457 = 16A .: Inductor does not allow sudden change of worest, I cot)= 16). : curent at at t:o, after switch is opened, Icot)= 16A I for t>o, switch is removed and corruit is drausas more IH figure o 4.2 vez an

after long time, ie, at tto. entire incluctor will fully dissipate across the resistence as no scolore is connected to it. Icon= OA current through inductor is given as, I(t) = I post Piros - I loos] e te where to the where Rea is the equivalent impedence across includes formind, 30 an 200 equivalent resistance of 48 and ae in series is, Reqs - (+2) 2 => Reag=652 equivalent resistance of Read & 3r is, hea 4 React Reque - Reqs 2016 tal Rea ': L=1H, TE IS } t = 0.55 IH)=(0+ (16-0) e-tos la IH)= 16 e-at a

:: lurrent through inductees fortzo is, ICF) = 16e-2t Al tzo is drawn as equivalent coicant for 320 At times Ve}an 341 loco equivalent rexistence across incluefcern terminals is determined earlier and equal to Req=202 Hence equivalent circuit is drawn as Rea Romano :. Potential across AP D, VAD = I1+xRea VAD= 16 e 2txau VAD: 32e-2t v s current across 20 branch is, Illt) - VAD 2+4) Is(t) = 32e2t A 6 Avea I, (+7=(25) => Vc: 32 e 2ta u Vc? 10.67e-at u C. voltage ve tour +20 is. Vc = 10.67e-2t v7