Question

3. Each pole of a 100 kW, 250 V short-shunt flat-compound generator has a shunt field of 2000 turns and a series field of 7 turns. If the series-field resistance is 0.01 and total shuntfield resistance is 100 2. Calculate the mmf when the machine operates at (a) no-load and (b) full-load Circuit Calculation(s) ha armature is connecte

Answer 1

short-shunt flor Compound generator:- circuit Full Load Calculation (s) Rses Sense IL 100 1103 sh Ise e 100xw mish 2500 250 400 Amp Vsha 250+400 (Rse) Vshe 50+C 400 X010) Vsh) = 254 Voit Rse = 0.01) Rsn = 1002) Nsh = 2000 Tuins Nse = 7 turns Ishs 254 -2.54 amp 100 shont fieldmme = Nsh Ish 3. (2000)(2.54) 5080 A Tapere tuins; Series field mnf = Nse Ise = 7x1400) - 2800 Tocal mmf = 5080 +2.800 = 7880 Ampere - tuin, at no-load Series field mmf = Nse Ise = 0; ( Ise=0) series field drop=zero; shunt fieldmmfe Nsh ish hla, 2 sov; nosobo Ish 250 -2.5 Amp, 200 Nsh Ish- 2.5x2.000 = 5000 AT Cs ScaTotaj ampere turns Care

... Terminent magnet DC motor cercuit:- Ra la when V = 90; speed (N) = 36001pm E = V-Ia Rai Ra neglected E OV=90, we know E = t.com £ x $wm A E = Km.wm 96K2.8C3600) km = 0.23 8 var - rad. a) armature voltage Required to motor runs torruns at 2720 rpm E km.wm') E = 0.238.620 602 720) E = 67079 volte armature voltage Required to motor Yons a C 1600rpm E = km.wm E = 6.238) / 2.8.1600) le e 39.87 v010 CS Scanned with CamScanner