Question

1. A 12g bullet moving horizontally with a velocity of 1000 m/s strikes and remains in a 3.0 kg block initially at rest on the middle of a 2 m wide table. The block, which is initially 80 cm above the floor, after traveling 1.00 m along the table top (frictional surface) strikes the floor a horizontal distance of 240 cm from its original position (140 m from the edge of the table). (i) Calculate the velocity of the block and the bullet as soon as bullet got stuck? (ii) Calculate the kinetic energy of the system for the part (i)? (iii) Calculate the velocity of the block as it leaves the table?

Answer 1

m, = 0.012 at the lus tet cammon spe ed got stuck in black is v C) Couservation of Linear momentum 刁 V = 0.012 X 1000 m/s +。 (ii )) Kinetic energy at instant bullet got sdutt- 804n 2uDcm k =23,9048 J ii) kivrate )haequation aloug y direchon 2 edge of dable 2

iematic. nx direction accelaration is zero akso time token to fall dousn ve itically wide be same in hornzouaQ travel of lyo om . let speed n hen diechon at edze of dable x 3.4645 m/s