Question

A particular electric dipole consists of a proton of charge of 1.6x10-19 Coulomb
and an electron of charge of -1.6x10-19 Coulomb, separated by 2x10-10[m] = 0.2[nm].
1a. What’s the electrostatic force between the charges (magnitude and direction), and
why?

1b. What’s the electric field magnitude and direction at a point halfway between the two
charges, and why?

1c. How much energy (in electron Volts OR in Joules) is needed to separate these two
charges?

1d. If these two charges “fell into” that dipole state from widely separate locations,
emitting the excess energy above in the form of a single photon, what’s the frequency of
the emitted photon?

1e. Given the frequency of this photon, what’s its wavelength and is it in the visible,
infrared, or ultraviolet?

Answer 1

(la) ta -q 2 Force, F = kq 82 =9x10x (1.681019) (2 x 10102 -9 = F = 5.76 x 10 N Direction of force is A towards each ther as shown and it is alteractive. (lb) ta 0 .q Eg Eq С Net field at midpoint o' E = 2lEnI -21E » E= 2 ( x ) = 8x9x10²x libx10's (2x10102 28.8 x 10" / towards Negaliwe Clarge Needed to seperate these two charges is, 9x100x (1.6x101972 10 E = (10) Ener V- 4-то я 2x 1010 -19 V = 11.52 x 10 J ✓