Question

An electron (mass 9.11×10^-31 kg, charge -1.602×10^ -19 C)is placed in a uniform electric field, E=5000N/C....

An electron (mass 9.11×10^-31 kg, charge -1.602×10^ -19 C)is placed in a uniform electric field, E=5000N/C. A) what is the change in electric potential if the election moves 1cm in the direction of the electric field? B)What is the change in electric potential energy if the electron moves 1 cm in the direction of the electric field?C) What is the change in electric potential if the election is 1 cm perpendicular to the electric field?D) What is the change in electric potential energy if the electron moves 1 cm perpendicular to the electric field?

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Change in potential energy, (Potential energy ) initial (potential energy) final Work done b) F =qE S s 1 cm -2 so, workdone

Add a comment
Know the answer?
Add Answer to:
An electron (mass 9.11×10^-31 kg, charge -1.602×10^ -19 C)is placed in a uniform electric field, E=5000N/C....
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • An electron (mass 9.11×10^-31 kg, charge -1.602×10^ -19 C)is placed in a uniform electric field, E=5000N/C....

    An electron (mass 9.11×10^-31 kg, charge -1.602×10^ -19 C)is placed in a uniform electric field, E=5000N/C. A) what is the change in electric potential if the election moves 1cm in the direction of the electric field? B)What is the change in electric potential energy if the electron moves 1 cm in the direction of the electric field?C) What is the change in electric potential if the election is 1 cm perpendicular to the electric field?D) What is the change in...

  • A proton (mass 1.67x10^-27 kg, charge 1.602x10^-19 C) is placed in a uniform electric field, E=5000...

    A proton (mass 1.67x10^-27 kg, charge 1.602x10^-19 C) is placed in a uniform electric field, E=5000 N/C. a) What is the change in electric potential if the proton moves 1 cm in the direction of the electric field? b) What is the change in electric potential energy if the proton moves 1 cm in the direction of the electric field? What is the change in electric potential if the proton moves 1 cm perpendicular to the electric field? d) What...

  • estion Completion Status: QUESTION 23 A proton (mass 1.67x10^-27 kg, charge 1.602x10^-19 C) is placed in...

    estion Completion Status: QUESTION 23 A proton (mass 1.67x10^-27 kg, charge 1.602x10^-19 C) is placed in a uniform electric field, E=5000 N/C. a) What is the change in electric potential if the proton moves 1 cm in the direction of the electric field? b) What is the change in electric potential energy if the proton moves 1 cm in the dilection of the electric field? c) What is the change in electric potential if the proton moves 1 cm perpendicular...

  • Given that mass of an electron is 9.11 x 10-31 kg and its charge is 1.602...

    Given that mass of an electron is 9.11 x 10-31 kg and its charge is 1.602 x 10-19 C, find its charge-to-mass ratio of the electron.

  • Consider an electron, of charge magnitude e 1.602 x1019 C and mass me 9.11 x 10-31...

    Consider an electron, of charge magnitude e 1.602 x1019 C and mass me 9.11 x 10-31 kg, moving in an electric field with an electric field magnitude E-7 x 102 N/C, similar to what Thana observed in the simulation. Let the length of the plates be L = 50 cm, and the distance between them be d = 20 cm. Find the maximum speed, v, the electron could be moving if it enters the space halfway between and parallel to...

  • An electron (mass m = 9.11 x 10-31 kg, charge e = 1.6 x 10-19 C)...

    An electron (mass m = 9.11 x 10-31 kg, charge e = 1.6 x 10-19 C) are accelerated from rest through a potential difference V = 450 V and are then deflected by a magnetic field (B = 0.4 T) that is perpendicular to their velocity. The radius of the resulting electron trajectory is:

  • 1. An electron (q = -1.6x10-19 C, m=9.11x10-31 kg) is placed in an electric field of...

    1. An electron (q = -1.6x10-19 C, m=9.11x10-31 kg) is placed in an electric field of magnitude 3.52x104N/C which points in the positive z direction. Calculate the magnitude and direction of the acceleration of the electron. 2. An electron is initially moving in the +z direction, with a speed v=2.54x105 m/s at z=0. In the region between z=+1.50 cm and z=+2.50 cm, there is a uniform electric field of magnitude 4.10x104 N/C in the +x direction. Outside that region (z...

  • An electron of mass m.-9.11 × 10-31 kg and a charge of ge -1.60 × 10-19...

    An electron of mass m.-9.11 × 10-31 kg and a charge of ge -1.60 × 10-19 C is released, from rest, in a region of uniform electric field that points to the right with a magriitude of E-3.65 N/C. How long does it take for the electron to reach a speed of 5.69 x 104 m/s? Assume the experiment is performed in a vacuum and that you can ignore the effects of gravity and friction. Give you answer in seconds...

  • An electron is placed in a uniform electric field of 5 × 105 N/C that points...

    An electron is placed in a uniform electric field of 5 × 105 N/C that points to the right. (e = 1.6 × 10-19 C, melectron = 9.11 × 10-31 kg). What is the magnitude of the force on the electron?

  • An electron of mass me=9.11×10−31 kg and a charge of qe=−1.60×10−19 C is released, from rest,...

    An electron of mass me=9.11×10−31 kg and a charge of qe=−1.60×10−19 C is released, from rest, in a region of uniform electric field that points to the right with a magnitude of | ​E ​⃗ ​​∣=6.83 N/C . How long does it take for the electron to reach a speed of 4.59 x 104 m/s? Assume the experiment is performed in a vacuum and that you can ignore the effects of gravity and friction. Give you answer in seconds using...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT