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An electron of mass me=9.11×10−31 kg and a charge of qe=−1.60×10−19 C is released, from rest,...

An electron of mass me=9.11×10−31 kg and a charge of qe=−1.60×10−19 C is released, from rest, in a region of uniform electric field that points to the right with a magnitude of | ​E ​⃗ ​​∣=6.83 N/C . How long does it take for the electron to reach a speed of 4.59 x 104 m/s? Assume the experiment is performed in a vacuum and that you can ignore the effects of gravity and friction. Give you answer in seconds using the exponential form (i.e., use 1.23e-4 to represent 123.4 microseconds rather than 0.0001234).

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Answer #1

Force = qE = ma

Acceleration = qE / m

-19 /2 -199 36 X/02 t 3.826 x10

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