Force = qE = ma
Acceleration = qE/m
An electron of mass me 9.11 x 10-31 kg and a charge of ge1.60 x 10-19...
An electron of mass m.-9.11 × 10-31 kg and a charge of ge -1.60 × 10-19 C is released, from rest, in a region of uniform electric field that points to the right with a magriitude of E-3.65 N/C. How long does it take for the electron to reach a speed of 5.69 x 104 m/s? Assume the experiment is performed in a vacuum and that you can ignore the effects of gravity and friction. Give you answer in seconds...
An electron of mass me=9.11×10−31 kg and a charge of qe=−1.60×10−19 C is released, from rest, in a region of uniform electric field that points to the right with a magnitude of | E ⃗ ∣=6.83 N/C . How long does it take for the electron to reach a speed of 4.59 x 104 m/s? Assume the experiment is performed in a vacuum and that you can ignore the effects of gravity and friction. Give you answer in seconds using...
Please show all work and equations! An electron of mass me 9.11 x 10-31 kg and a charge of ge-1.60 x 10-19 C is released, from rest, in a region of uniform electric field that points to the right with a magnitude of E 3.23 N/C. How long does it take for the electron to reach a speed of 2.64 x 10 m/s? Assume the experiment is performed in a vacuum and that you can ignore the effects of gravity...
An electron of mass me = 9.11x 10^-31kg and a charge of qe = -1.60 x 10^-19 is released, from rest, in a region of uniform electric field that points to the right with a magnitude of E=3.43 N/C. How long does it take for the electron to reach a speed of 4.49 x 104 m/s? Assume the experiment is performed in a vacuum and that you can ignore the effects of gravity and friction.
An electron (me = 9.11 x 10-31 kg) orbits counterclockwise in a horizontal xy-plane with a diameter of 2.5 cm and with a frequency of 2.4 GHz within a region of uniform magnetic field. What is the kinetic energy (in units of 10-14 Joules) of the electron? An electron (me = 9.11 x 10-31 kg) orbits counterclockwise in a horizontal xy-plane with a diameter of 2.5 cm and with a frequency of 2.4 GHz within a region of uniform magnetic...
An electron (mass m = 9.11 x 10-31 kg, charge e = 1.6 x 10-19 C) are accelerated from rest through a potential difference V = 450 V and are then deflected by a magnetic field (B = 0.4 T) that is perpendicular to their velocity. The radius of the resulting electron trajectory is:
Given that mass of an electron is 9.11 x 10-31 kg and its charge is 1.602 x 10-19 C, find its charge-to-mass ratio of the electron.
The mass of an electron is 9.11 x 10-31 kg and the diameter of a hydrogen atom is 100 pm (100 x 10-12 m). As the electron could be located anyway throughout the volume of the hydrogen atom, the maximum uncertainty in the position of the electron, Ax, can be estimated to be < 100 pm. Determine the minimum uncertainty in the speed of an electron in a hydrogen atom.
A proton of mass mp= 1.67×10−27 kg and a charge of qp= 1.60×10−19 C is moving through vacuum at a constant velocity of 10,000 m/s directly to the east when it enters a region of uniform electric field that points to the south with a magnitude of E =3.62e+3 N/C . The region of uniform electric field is 5 mm wide in the east-west direction. How far (in meters) will the proton have been deflected towards the south by the...
An electron of mass 9.11×10−31 kg leaves one end of a TV picture tube with zero initial speed and travels in a straight line to the accelerating grid, which is a distance 1.70 cm away. It reaches the grid with a speed of 2.70×106 m/s . The accelerating force is constant. Find the acceleration. Find the time to reach the grid. Find the net force. (You can ignore the gravitational force on the electron).