use Heisenberg uncertainty principle,
Δx*Δv = h/(4*pi*m)
Here:
Δv = 1.0E-10 m
mass, m = 9.11*10^-31 Kg
Putting values,
1.0E-10*Δ v = (6.626*10^-34)/(4*3.14*9.11E-31)
1.0E-10*Δ v = 5.791*10^-5
Δv = 5.791*10^5 m/s
Answer: 5.79*10^5 m/s
The mass of an electron is 9.11 x 10-31 kg and the diameter of a hydrogen...
Heisenberg Uncertainty Principle • An electron has a mass of 9.11 x 10-31 kg and moves at an average speed of 5 x 10 m/s. Let's assume we know the speed to an uncertainty of 1%. • Calculate the uncertainty in the position of the electron. (4x)(mAv) 24 Friendly Reminders...
7. In the Bohr model of atomic hydrogen, an electron of mass 9.11 x 10-31 kg revolves around the proton in a circular orbit of radius .29 x 10-11 m. The proton and electron have equal charge magnitudes and the mass of the proton is 1.67 x10-27 kg. What is the radial acceleration of the electron? What is it's velocity? What is it's angular velocity?
To resolve an object in an electron microscope, the wavelength of the electrons must be close to the diameter of the object. What kinetic energy, Ek, must the electrons have in order to resolve a protein molecule that is 4.10 nm in diameter? Take the mass of an electron to be 9.11 x 10-51 kg. U Resources German physicist Werner Heisenberg related the uncertainty of an object's position (Ax) to the uncertainty in its velocity (Au) Ax > 4πmΔυ where...
Part A m, how fast is the The mass of an electron is 9.11 x 10-5 kg. If the de Broglie wavelength for an electron in a hydrogen atom is 3.31 x 10- electron moving relative to the speed of light? The speed of light is 3.00 x 10 m/s Express your answer numerically as a percent. View Available Hint(s)
An electron (me 9.11 x 10-31 kg) has a speed of 4 x 106 m/s. If the uncertainty in its energy is 8 ev, what is the uncertainty in its position? O 1.65 x 10-10 m 2.11 x 10-10 m 2.64 x 10-10 m 3.30 x 10-10 m 2.07 X10-9
Given that mass of an electron is 9.11 x 10-31 kg and its charge is 1.602 x 10-19 C, find its charge-to-mass ratio of the electron.
In a laboratory experiment, an initially stationary electron (mass = 9.11 x 10-31 kg) undergoes a constant acceleration through 1.5 cm, reaching a speed of 4.0 x 106 m/s at the end of that distance. What are (a) the magnitude of the force accelerating the electron and (b) the electron's weight? (a) Number Units (b) Number Units
An electron of mass 9.11 x 10-31 kg has an initial speed of 4.00 x 105 m/s. It travels in a straight line, and its speed increases to 7.60 x 105 m/s in a distance of 4.20 cm. Assume its acceleration is constant. (a) Determine the magnitude of the force exerted on the electron. N (b) Compare this force (F) with the weight of the electron (F), which we ignored. F ܗܝ| ܝ
An electron of mass 9.11 x 10-31 kg has an initial speed of 2.40 x 105 m/s. It travels in a straight line, and its speed increases to 7.20 x 10 m/s in a distance of 5.60 cm. Assume its acceleration is constant. (a) Determine the magnitude of the force exerted on the electron 4.11429e 12X Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. N (b) Compare this force...
Review | Constants 1 Periodic Table The mass of an electron is 9.11 x 10 1 kg. If the de Broglie wavelength for an electron in a hydrogen atom is 3.31 x 100 m, how fa is the electron moving relative to the speed of light? The speed of light is 3.00 x 10 m/s. Express your answer numerically as a percent. View Available Hint(s) 90 AED O ? Submit Part B The mass of a golf ball is 45.9...