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In a laboratory experiment, an initially stationary electron (mass = 9.11 x 10-31 kg) undergoes a constant acceleration throu

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Answer #1

Accleration (a)

a=\frac{v^2}{2*d}=\frac{(4.0\times 10^6)^2}{2*0.015}=5.33\times 10^{14} m/s^2

Force = m*a= 9.11*10-31 *5.33*1014= 4.856 -16 N

b) Weight = 9.11*10-31 *9.8 = 89.279 N

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