Question

A proton (mass 1.67x10^-27 kg, charge 1.602x10^-19 C) is placed in a uniform electric field, E=5000 N/C. a) What is the change in electric potential if the proton moves 1 cm in the direction of the electric field? b) What is the change in electric potential energy if the proton moves 1 cm in the direction of the electric field? What is the change in electric potential if the proton moves 1 cm perpendicular to the electric field? d) What is the change in electric potential energy if the proton moves 1 cm perpendicular to the electric field? ni aur work

Answer 1

a) ΔV = -Ed

= 5000×0.01 V

= - 50 V

b ) ΔU = qΔV

= 1.602×10⁻¹⁹×-50 J

= -8.01×10⁻¹⁸ J

c) ΔV = 0V

d) ΔU = 0J as E̅.ds̅ = 0