4. An electric field of 5000 N/C is in the +y direction. A charge of 3.0 μC is brought a distance...
A constant electric field is in the positive X direction as shown in the diagram below. Also shown are two paths through which a charge can move from point A to point C. In the first path, the charge moves directly from A to C. In the second path path the charge moves parallel to the Y-axis to B and then parallel to the X-axis to C. Select greater than, less than or equal to for the following statements. greater...
A charge moves a distance of 1.8 cm in the direction of a uniform electric field having a magnitude of 249 N/C. The electrical potential energy of the charge decreases by 117.7 × 10−19 J as it moves. Find the magnitude of the charge on the moving particle. The electrical potential energy depends on the distance moved in the direction of the field. Answer in units of C.
deal with the following diagram, showing three point charges of -2.00 μC, +4.00 μC, and +6.00 μC that are placed along the x-axis. (a)What is the sign of the electric potential at point P? positive negative (b) What is the magnitude of the electric potential at point P? (c)Suppose a proton is initially very far away in the +y direction. How much work would it take to bring this proton down along the y-axis to point P? (d)Would your answer...
A uniform electric field of magnitude 214 V/m is directed in the positive y direction. A +14.3 μC charge moves from the origin to the point (x, y) = (21.3 cm, 50.9 cm). What was the change in the potential energy of this charge? Through what potential difference did the charge move?
A proton (mass 1.67x10^-27 kg, charge 1.602x10^-19 C) is placed in a uniform electric field, E=5000 N/C. a) What is the change in electric potential if the proton moves 1 cm in the direction of the electric field? b) What is the change in electric potential energy if the proton moves 1 cm in the direction of the electric field? What is the change in electric potential if the proton moves 1 cm perpendicular to the electric field? d) What...
A 7.2 N force acts on a 3.65 μC charge as the charge moves from x = 0 to x = 35 cm. a) What is the change in the potential energy of the charge? b) What is the electric potential difference between x = 0 to x = 35 cm? (give the absolute value)
Find the magnitude and direction of the net electric field at point A. The two particles in the diagram each have a charge of +7.3 μC. The distance separating the charges is 7.0 cm. The distance between point A and B is 4.0 cm.
A uniform electric field of magnitude 232 V/m is directed in the positive y direction. A -14.9 μC charge moves from the origin to the point (x, y) = (20.4 cm, 52.8 cm). What was the change in the potential energy of this charge? Through what potential difference did the charge move? Please explain and go step by step. Thank you.
Help 2) The electric field E 5000 N/C , charge q-2 C ' mass m :5 grams. Calc. qE, then apply the acceleration of this charge. Hint: calc. force F newton's 2nd law. A) 1 m/s2 B) 2 m/s2 C) 3 m/s2 D) 4 m/s2 3) The electric field is E 10,000 N/Ci, displacement d - 5 cm at 60 (angle relative to positive x axis), charge q charge in microJoules (106 J) A) 1.25 B) 2.5 C) 3.75 D)...
A uniform electric field with a magnitude of 5500 N/C points in the positive x direction. Find the change in electric potential energy when a +11.5-μC charge is moved 6.50 cm in the positive x direction Find the change in electric potential energy when a +11.5-μC charge is moved 6.50 cm in the negative x direction. Find the change in electric potential energy when a +11.5-μC charge is moved 6.50 cm in the positive y direction.