Question

A.

3 of 11 (9 complete) HW Score: 63.64%, 7 of 11 pts Score: 0 of 1 pt X 6.6.9-T Question Help Use a normal approximation to finB.

Score: 0 of 1 pt 5 of 11 (9 complete) HW Score: 63.64%, 7 of 11 pts X 6.6.15-E Question Help Based on a smartphone survey, asC.

6.6.18-T Question Help O Assume that 30.1% of people have sleepwalked. Assume that in a random sample of 1492 adults, 489 havD.

6.6.20 Question Help O In a study of 451,864 cell phone users, it was found that 152 developed cancer of the brain or nervous

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Answer #1

Question A)

The number of eligible voters who voted out of 188 could be modelled here as:

X ~ Bin(n = 188, p=0.22)

This can be approximated as a normal distribution as:

Y Nu = np,o= V np(1-p))

Y \sim N(\mu = 188*0.22 , \sigma = \sqrt{188*0.22*0.78})

Y ~ Nu = 41.36,0 = 5.6799)

The probability that fewer than 45 voters voted is computed here as:
P(Y < 45)

Converting it to a standard normal variable, we get here:

45 – 41.36 P(Z <= 5,6799

P(Z < 0.6409)

Getting it from the standard normal tables, we get here:

P(Z < 0.6409) = 0.7392

Therefore 0.7392 is the required probability here.

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