Question

3. In a completely randomized design, 5 experimental units were used for each of the four levels of the factor. F Sum of Squares 385.12 Degrees of Freedom Source of Variation Treatment Error Total Mean Square 1563.71 a. Complete the ANOVA table. b. Find the critical value at the 0.05 level of significance from the F table for testing whether the population means for the three levels of the factors are different. c. Use the critical value approach and a = 0.05 to test whether the population means for the three levels of the factors are the same.

Answer 1

Ans: 3 SSE a SST Sst = 1563.71-385.12 = 2178.59 DF = 5 ) = 4 DFE (5-2x (4-1) = 4x3 =12 DET Dff + DfE 4+12=16 385.12 MSE 4 GSE MSE 1178.59 12 MSE f 0.9803 MSE 96.28 SS+/oft Elofe 98.22 Source of Variation Sum of Degree of Squares freedom Mean Square 96.28 385.12 4 0.9803 Treatments Exor Total 1178.59 12 98.22 1563.21 16 こ 13.2592 & critical value £4,12,0.05 c) Sonce fszat <fc, we fail to reject to. There as no enough extence to Gonclude that the population means for 3 levels of factors are different