Question

2. Two team (A and B) play a series of baseball games. The team who wins three games of five-game-series wins the series. Consider A has home-field advantage (0.7 means A has probability of winning 0.7 if it plays in its field) and opponent-field disadvantage (0.2 means A has probability of winning 0.2 if it plays in opponents field). If the series start on A team's field and played alternately between A and B team's fields, find the probability that series will be completed in four games. (14)

i need help ASAP thanks

Answer 1

Solm P(A win at own home ground) = 7 P(A win at Opponent ground) = 2 10 p(B win at Ais ground) = 20 P(B win at own home ground) = 8 4 games. Starts the series with Ais ground. Pl series completed in 4 games) = ? Home Series will be completed when either for B wins at least 3 matches out of 4 matches lelseries completed in 4 games) = - P(A wins at least three matches ) + p(B. wing at least three matchen) X: A win the match : #Series: A B AB. P(X2,3) = P(x=3) + P(X= 42 z ( WWW2) + (WWLW) + (WLWW) + (LWww) +(wwwing - (2x Box ***$)+1***(7* * * * *) + ( B ) + (7 yo v * ) 784+ 847 784 +84+196 Scanned with CamScanner 10000 10000

Y: B wing the match PLY? 3) = P(Y=3) + P(Y24) - (WWWL) + (WWLW)+ (WLWW) + (LWWW)+(www. - (**.***+(****$)+ (%*X* )+ 3552 2 144+ 13u4+ 98 +1344 +144+ 576 19000 - 35512 -@ plsernes Completed in A game) = P(X23) + P(723) = 19,820 + 352 sy to leave p(semes completed in 4 games) = 0.5484 Scanned with CamScanner