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(on this page, A, B, C, D are all positive integers and A/B <C/D.) We saw in the previous assignment that CA CB - AD 1 DB=BD

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S.CD are all buitine integers 1.) We shall now show that Now A+C BTD Автос — А3 — AD B(@+) _ BC-AD B (6 +0) 0 1. Now since NoАТc BTD Again consider Ate § - Ate BTD - CB+eD- AD - CD 1. D (BxD) — eB – AD D(Bto) 70 L CB-AD TO and A, B, C, D are all posi

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