Question

A survey of 1,680 randomly selected adults showed that 549 of them have heard of a new electronic reader. The accompanying technology display results from a test of the claim that 37% of adults have heard of the new electronic reader. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.01 significance level to complete parts a through e Sample proportion: 0.326786 Test statistic Critical z: P-Value z:-3.6687 ± 2.5758 0.0002 a. Is the test two-tailed, left-tailed, or right-tailed? O Right tailed test c. What is the P-value? P-value- (Round to four decimal places as needed.) d. What is the null hypothesis and what do you conclude about it? Two-tailed test O Left-tailed test b. What is the test statistic? Identify the null hypothesis A. Ho :p #0.37 O B. Ho p> 0.37 C. Ho , p<0.37 O D. Ho p 0.37 (Round to two decimal places as needed.) Choose the correct answer below O A. Reject the null hypothesis because the P-value is less than or equal to the significance level, a. O B. Fail to reject the null hypothesis because the P-value is greater than the significance level, a. ( C. Reject the null hypothesis because the P-value is greater than the significance level, ?. O D. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, oa e. What is the final conclusion? A. There is not sufficient evidence to warrant rejection of the claim that 37% of adults have heard of the new electronic reader O B. There is not sufficient evidence to support the claim that 37% of adults have heard of the new electronic reader ° C. There is sufficient evidence to warrant rejection of the claim that 37% of adults have heard of the new electronic reader D. There is sufficient evidence to support the claim that 37% of adults have heard of the new electronic reader

Answer 1

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