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A survey of 1 comma 567 randomly selected adults showed that 570 of them have heard...

A survey of 1 comma 567 randomly selected adults showed that 570 of them have heard of a new electronic reader. The accompanying technology display results from a test of the claim that 38​% of adults have heard of the new electronic reader. Use the normal distribution as an approximation to the binomial​ distribution, and assume a 0.05 significance level to complete parts​ (a) through​ (d. Sample​ proportion: 0.363752 Test​ statistic, ​z: negative 1.3251 Critical​ z: plus or minus1.9600 ​P-Value: 0.1852 a. Is the test​ two-tailed, left-tailed, or​ right-tailed? ​Left-tailed test ​Two-tailed test Right tailed test b. What is the​ P-value? ​P-valueequals 0.1852 ​(Round to four decimal places as​ needed.) c. What is the null hypothesis and what do you conclude about​ it? Identify the null hypothesis. A. Upper H 0 : p greater than 0.38 B. Upper H 0 : p less than 0.38 C. Upper H 0 : p equals 0.38 D. Upper H 0 : p not equals 0.38

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