Question

Consider three charges arranged in a triangle as shown. Y 8.1 nC 0.748 m G4 4.4 nc 0.284 m -2.2 nC What is the net electric force on the charge at the origin? The value of the Coulomb constant is 8.99 x 109 Nm²/C2. Answer in units of N. 002 (part 2 of 4) 10.0 points What is the direction of this force (as an angle between – 180° and +180° measured from the positive x-axis, with counterclockwise posi- tive)? Answer in units of°. 003 (part 3 of 4) 10.0 points What is the magnitude of the net electric field at the position of the charge at the origin? Answer in units of N/C. 004 (part 4 of 4) 10.0 points What is the direction of the net electric field (as an angle between –180° and +180° mea- sured from the positive x-axis, with counter- clockwise positive). Answer in units of°.

Answer 1

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0-748m 4.40L E = 9x / x44x19 (0.748)2 = 70.7769/ E = 9x8+2.2018 - = 245.4878 (0.284)2 - 243 IL - Ello. 284m 72. 200 Enet = ? + (-E2%) = -70.7769 ↑ -245-4873 a) Force on 8.inc = q Enet = 8-1x10? (J670.776) ?(245.48732) - Fnet - 2.869444106N) And I b) Direction, tano = -245-487 -70.7769 o=73.917° (from =X-axis) or 0 = -(106.083") ] And 73.97 at fuet 2 d) Enet = J 170-7769)4/245.487)2 = 255. 486 Ny Direction, 0= -106-0830 AM