To Test :-
Mean tenure for CEO was atleast 11 years
H0 :-
H1 :-
Part b)
t value
Looking for the t value in t table across n-1 degree of freedom i.e 80 - 1 = 79 DF for 1 tailed
we can see that | t | = 0.397 lies between values 0.000 & 0.678 that has P value between 0.50 & 0.25
0.25 < P value < 0.50
P Value = 0.346 calculated on excel
Part c)
Reject null hypothesis if
- 0.397 < 2.374, hence we fail to reject null hypothesis
Conclusion :- Accept null hypothesis
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