Question

Read both options and complete only one of them. Remember, d = 1/2at2 is the equation for an object that starts at rest.

Option One

Materials: Calculator

1. In the table below, you are given the height from which various objects fell and the time it took for those objects to fall on Earth, the moon, and Mars. Use the data to calculate the acceleration due to gravitational force at each location.

   	Earth		Moon		Mars
   Distance (m)	2.25	3.08	4.04	4.57	4.68	3.55
   Time (s)	0.680	0.793	2.20	2.26	1.58	1.38
   Acceleration due to gravity (m/s2)
   Average g value for the location (m/s2)

2. What to submit:

1. Your completed table with calculations for acceleration due to gravitational force and the average value.

2. All work shown for your calculations.

Answer 1

SOLUTION :

s = 0 + 1/2 g t^2

=> g = 2s / t^2 

=> g = 

Earth :

g earth1 = 2*2.25 / (0.680)^2 = 9.732 m/s^2

g earth2 = 2*3.08/0.793^2 = 9.796 m/s^2

avg. g earth = (9.732 + 9.796) / 2 = 9.764 m/s^2

Moon :

g moon1 = 2*4.04 / 2.20^2 = 1.669 m/s^2

G moon2 = 2*4.57 / 2.26^2 = 1/789 m/s^2

avg. g moon = (1.669 + 1.789) / 2 = 1.729 m/s^2 

Mars :

g mars1 = 2*4.68 / 1.58^2 = 3.749 m/s^2

g mars2 = 2*3.55 / 1.38^2 = 3.728 m/s^2

avg. g mars = (3.749 + 3.728 ) / 2 = 3.739 m/s^2 

Accordingly, table will be as under :

Particulars / Planet                                        Earth                 Moon                    Mars

Distance  (m)                                           2.25     3.08        4.04     4.57         4.68     3.55

Time (s)                                                   0.68     0.793       2.20    2.26         1.58     1.38

Acceleration due to gravity m/s^2          9.732.  9.796.      1.669  1.789        3.749.  3.728

Average g value for location m/s^2               9.764                  1.729                   3.739