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Ch.5 -Circular Motion

6. According to Newton's Law of Gravitation, if the distance between two bodies is doubled, the attractive force between them becomes ( twice as large. Show reasoning: 0 half as large. four times as large. ( one quarter as large. 0 unchanged. fourt Kepler's third law can be simplified to T/r=1 or Tar if the orbit period T is expressed in earth years and r in Astronomical Units (A.U.), the sun-earth distance. (1 A.U. = 1.5x10 m) 0 7. Calculate how long it takes Mars in earth years for one trip around the sun by using an average Sun-Mars distance of 1.5 A.U. 0 0.735 earth years Show calculation: 1.84 earth years ( 3.37 earth years ( 164 earth years 8. Calculate how long it takes Neptune in earth years for one trip around the sun by using an average Sun-Neptune distance of 30 A.U. 0 0.735 earth years Show calculation: 1.84 earth years 0 3.37 earth years ( 164 earth years 0 9.-10. Find the gravitational force (the weight) of a 75 kg person standing on the surface of the earth. a) By using the gravitation acceleration g = 9.8 m/s ( 9.8 m/s2 Show calculation: ( 9.8 N 0 735 N ( 737 N b) By using Newton's law of gravitation. (See sample exercise "try this box 5.2") m=5.98x10 kg 0 9.8 m/s? Show calculation: r = 6.37 x 10m 0 9.8 N G=6.67 x 10" Nm /kg 0 735 N ( 737 N

Answer 1

6 A ccording to Newton's Law of gravitation - F 2 1 2 iie Force(f) between 2 proportional to squase between the masses, mares is inversely of distance (m) ת ח we n2 m 7 ha 7 fz-) new Y fg old 1 r2 new he old old fence i ust force force distance distance T NU if $2= 2(84) fa - 12,5 (1j* TF2 = fj] So, fonce will be . One quarter lange @